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C++ Institute CLA - C Certified Associate Programmer Sample Questions:

1. What happens if you try to compile and run this program?
#include <stdio.h>
int main (int argc, char *argv[]) {
int i = 7 || 0 ;
printf("%d", !! i);
return 0;
}
Choose the right answer:

A) The program outputs 7
B) Compilation fails
C) The program outputs 1
D) The program outputs 0
E) The program outputs -1

2. What happens if you try to compile and run this program?
#include <stdio.h>
int main (int argc, char *argv[]) {
int i = 1;
for( ;; i/=2)
if(i)
break ;
printf("%d",i);
return 0;
}
Choose the right answer:
The program executes an infinite loop

A) The program outputs 0.5
B) Compilation fails
C) The program outputs 1
D) The program outputs 0

3. What happens if you try to compile and run this program?
#include <stdio.h>
int main (int argc, char *argv[]) {
int i = 20;
printf("%x", i);
return 0;
}
-
Choose the right answer:

A) The program outputs 20
B) The program outputs 24
C) The program outputs 14
D) Compilation fails
E) The program outputs 10

4. Assume that ints are 32-bit wide.
What happens if you try to compile and run this program?
#include <stdio.h>
typedef union {
int i;
int j;
int k;
} uni;
int main (int argc, char *argv[]) {
uni s;
s.i = 3;
s.j = 2;
s.k = 1;
printf("%d",s.k * (s.i - s.j));
return 0;
}
Choose the right answer:

A) The program outputs 3
B) The program outputs 9
C) Compilation fails
D) The program outputs 0
E) Execution fails

5. What happens if you try to compile and run this program?
#include <stdio.h>
int main (int argc, char *argv[]) {
int i = 1;
for(;i > 128;i *= 2);
printf("%d", i) ;
return 0;
}
-
Choose the right answer:

A) The program outputs a value greater than 128
B) Compilation fails
C) The program outputs a value less than 128
D) The program outputs 128
E) The program enters an infinite loop

Solutions: